Mathematics, 12.02.2021 01:00 jasminechambers642

Maclaurin Series: Show that ln(e^2x + e^-2x ) is equal to a + bx^2 (Part ii only)

I'd really appreciate an explanation for part ii :,) Thanks in advance!

Maclaurin Series: Show that ln(e^2x + e^-2x ) is equal to a + bx^2

(Part ii only)I'd really appre

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Maclaurin Series: Show that ln(e^2x + e^-2x ) is equal to a + bx^2 (Part ii only)

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Maclaurin Series: Show that ln(e^2x + e^-2x ) is equal to a + bx^2 (Part ii only)I'd really appreciate an explanation for part ii :,) Thanks in advance!

Answers

Another question on Mathematics

Maclaurin Series: Show that ln(e^2x + e^-2x ) is equal to a + bx^2 (Part ii only)

I'd really appreciate an explanation for part ii :,) Thanks in advance!