Mathematics, 12.02.2021 02:00 rschaum08
Given: \angle BAC \cong \angle ACD∠BAC≅∠ACD and \angle ADB \cong \angle DBC.∠ADB≅∠DBC.
Prove: ABCDABCD is a parallelogram.
What are the extra steps?
Answers: 1
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Given: \angle BAC \cong \angle ACD∠BAC≅∠ACD and \angle ADB \cong \angle DBC.∠ADB≅∠DBC.
Prove: ABCDA...
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