Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $30,000 and $50,000. Assume that a 95% confidence interval estimate of the population mean annual starting salary is desired. Given the information in the Microsoft Excel Online file below, construct a spreadsheet to determine how large a sample should be taken for each desired margin of error.

A. 384.16

B. 2,401

C. 9,604

D. No

Step-by-step explanation:

Calculation to determine how large a sample should be taken for each desired margin of error

First step is to find σ which represent Population Standard deviation

σ=($50,000-$30,000)/4

σ=$20,000/4

σ = 5,000

Now let calculate how large a sample should be taken for each desired margin of error

Using this formula

n = (Za/2*σ/E)^2

Where,

Za/2=1-0.95/2

Za/2=0.05/2

Za/2=0.025

Z-score 0.025=1.96

Za/2=1.96

σ =5,000

E represent Desired margin of error

Let plug in the formula

a. $500

n = (1.96* 5,000/$500)^2

n=(9,800/$500)^2

n=(19.6)^2

n = 384.16

b. $200

n = (1.96*5,000/200)^2

n=(9,800/$200)^2

n=(49)^2

n = 2,401

c. $100

n = (1.96*5,000/$100)^2

n=(9,800/$100)^2

n=(98)^2

n = 9,604

Therefore how large a sample should be taken for each desired margin of error will be :

A. $500= 384.16

B. $200= 2,401

C. $100= 9,604

d.NO, Based on the information calculation i would NOT recommend trying to obtain the $100 margin of error reason been that it is highly costly compare to $500 margin of error and $200 margin of error.

2

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."