A force of 192 lb is required to hold a spring stretched 3 ft beyond its natural length. How much work W is done in stretching it from its natural length to 6 inches beyond its natural length

The work done in stretching the spring is 8 lb.ft

Step-by-step explanation:

Given;

Applied force, F = 192 lb

extension of the spring, x = 3 ft

Determine the spring constant from the applied force and extension;

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;

x = 6 inches = 0.5 ft

Therefore, the work done in stretching the spring is 8 lb.ft

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

source

answer: finding the extract measurements and knowing the points

step-by-step explanation: