List the integers that satisfy both these inequalities.
Put the answers on one line.

-7, -6, -5, -4, -3

Step-by-step explanation:

Given:

2x + 5 < 0

x > -8

Thus, we can combine both statements to find out integers that satisfy both inequalities.

2x + 5 < 0

Let's find x

2x < 0 - 5 (substraction property)

2x < -5

Divide both sides by 2

x < -5/2

This implies that -5/2 is greater than the set of values of x.

The second inequality, x > -8 implies that -8 is less than the value of x.

Les combine both:

-8 < x < -5/2

Therefore, the possible set of integers are whole numbers between the range of -8 and -5/2 which excludes -8 and -5/2.

Thus, they are:

-7, -6, -5, -4, -3

im here

step-by-step explanation: