If f(x) = 4 – x^2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

a: 6 – 3 – (4 + 3)^2

b: 6 – 3 – (4 – 3^2)

c: 6(3) – 4 + 3^2

d: 6(3) – 4 – 3^2

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

what's that