S(t) = -16t^2+96t+256 the quadratic function models the balls height above the ground, s(t), in feet, t seconds after it was thrown when a person standing close to the edge on top of a 248-foot building throws a baseball ball vertically upward. When will the ball reach its maximum height, and what is the maximum height of the ball?

The ball reaches maximum height in 3 seconds.

The maximum height of the ball is of 400 feet.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

It's vertex is the point

In which

If a<0, the vertex is a maximum point, that is, the maximum value happens at , and it's value is

In this question:

The height is modeled by:

So, the coefficients are:

Instant of time the ball reaches maximum height:

The ball reaches maximum height in 3 seconds.

What is the maximum height of the ball?

This is s(3).

The maximum height of the ball is of 400 feet.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length