A Ferris wheel has a radius of 37 feet. The bottom of the Ferris wheel sits 0.6 feet above the ground. You board the Ferris wheel at the 6 o'clock position and rotate counter-clockwise. Write a function f that determines your height above the ground (in feet) in terms of the number of radians you have swept out from the 6 o'clock position, a.
f(a)=

Write a function g, that determines your height above the ground (in feet) in terms of the number of feet you have traveled since you started rotating, s.
g(s)=

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5104.38 inches

step-by-step explanation:

this is a very good question

step-by-step explanation:

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g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.