Aconcession stand sells hamburgers (h) for $2 and hotdogs (d) for $1. on friday night they sold a total of 300 hamburgers and hotdogs and made $420. how many of each did they sell? which system of equations matches the situation?

Number of hamburgers = 120

Number of hotdogs = 180

Step-by-step explanation:

A concession stand sells hamburgers (h) for $2 and hotdogs (d) for $1.

On Friday night they sold a total of 300 hamburgers and hotdogs and made $420.

We have to find the numbers of hamburgers and hotdogs.

Now we have to form the equations

h + d = 300(1)

2h + 1d = 420(2)

By subtracting equation 2 from 1.

2h + d - h - d = 420 - 300

h = 120

and from equation 1

d + 120 = 300

d = 300 - 120 = 180

Therefore total 120 hamburgers and 180 hotdogs were sold.

the solution is 12x-6y

after simplifying it i got: -36.25 as my answer. hope that !