Find two consecutive ODD integers such that: The square of the larger is 120 more than the square of the smaller

See explanation

Step-by-step explanation:

Le the number be x and x+2

The information given can be formed into and equation as:

(x + 2)² = x² + 120

(x + 2)(x + 2) = x² + 120

x² + 2x + 2x + 4 = x² + 120

Collect like terms

x² - x² + 2x + 2x = 120 - 4

4x = 116

x = 116/4

x = 29

The smallest number is 29

The larger number is x + 2 = 29 + 2 = 31

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

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step-by-step explanation: