What is the point-slope form of a line with slope -3 that contains the point
(10, -1)?

y + 1 = -3(x - 10)

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

Step-by-step explanation:

Step 1: Define

Slope m = -3

Point (10, -1)

Step 2: Write Function

Substitute in variables into general form.

y - -1 = -3(x - 10)

y + 1 = -3(x - 10)

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c