Mathematics, 13.02.2021 07:10 Thejollyhellhound20
Rectangle ABCD is shown with diagonal AC drawn. Point F is on AC and point E on DC such that FE is perpendicular to DC. Prove triangle ABC is similar to triangle CEF. Prove (BC)(CE= (AB)(EF)
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Rectangle ABCD is shown with diagonal AC drawn. Point F is on AC and point E on DC such that FE is p...
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