The spinner shown is divided into congruent sections that are labeled from 1 through 7. If the spinner is spun one time, what is the probability of the arrow NOT landing on a section labeled with an even number?

Step-by-step explanation:

Total outcome is 7

Favorable outcome is 4

The probability of the arrow NOT landing on a section labeled with an even number and landing on a section labeled with odd number is    

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.