A company that manufactures computer components has a 3% defective rate. If 10 components are randomly selected, find the probability of getting 2 defective components. Binomial Probability Formula: P(x) = nCx px qn-x

The probability of getting 2 defective items

P(X=2) = 0.0317416

Step-by-step explanation:

Step(i):-

Given that size of the components n = 10

Given that the probability of getting the defective item

           p = 3% = 0.03

           q = 1-p =1- 0.03 = 0.97

Let 'X' be a random variable in a binomial distribution

Step(ii):-

The probability of getting 2 defective items

P(X =2) = 45 × 0.000705

P(X=2) = 0.0317416

the answer is 3/5

step-by-step explanation:

first divide 24 divided by 8 because that is the least common multiple

then divide 40 by 8

then you will get 3/5.