A small point charge carries a charge of +4 x 10-10 C. 7.1 - Calculate the magnitude of the electric field strength at a distance of 30 mm
from the point charge.

7.2- A second point charge of -8 x 10-10 C is placed at position X. Calculate the
magnitude of the force between the charges.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

answer: this is not a question

step-by-step explanation: this is a answer

they go with it happens or they mite give a chance?

step-by-step explanation:

a

step-by-step explanation: