PLEASE HELP IM FAILING ALGEBRA!!
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The three dimensions are ( x-3)(x-1) and (x-4)

The missing dimension is x-4

Step-by-step explanation:

Step(i):-

Given that the polynomial

            x³ -8x²+19x -12=0

put x=3

 ⇒      27 -8(9)+19(3)-12 =0

          84-84 =0

            0=0

∴ x =3 is satisfies the given polynomial equation

one factor  x-3 =0

Step(ii):-

By using synthetic division method

     x=3     ↓     1    -8    19    -12

                ↓     0   3    -15     12

                      1   - 5      4       0  

The polynomial (x-3) ( x² -5x +4) =0

The factors of the given polynomial

             x-3 =0  and      x² - 5x +4 =0

                x =3   and   x² - 4x -x+4 =0        

                x =3   and  x( x-4) -1(x-4) =0

              ( x-3)    and (x-1)(x-4) =0

The three dimensions are ( x-3)(x-1) and (x-4)

Final -

The missing dimension is x-4

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

y=x+9

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step-by-step explanation: