Reflect triangle ABC over the x-axis. Then translate the new triangle 5 units to the left. What are the coordinates of the vertices of the final image? A. A’(-1, -8), B’(-2, -2), and C’(5, -2)
B. A‘ (-6, -8), B‘(-7, -2), and C‘(0, -2)
C. A‘(-1, 5), B‘(-3, -7), and C‘(5, -3)
D. A’(-5, 1), B’(-2, -7), and C‘(5, -7)

Hi there!

The answer to your question is B my explanation is below

The coordinates of the vertices of the final image will be:

A''(-6, 8), B''(-7, -2), and C''(0, -2)

Hence, option (B) is true.

Step-by-step explanation:

Given the triangle with the vertices

A(-1, -8)B(-2, 2)C(5, 2)We know that when we reflect a point across the x-axis, the x-coordinate remains the same, but the y-coordinate reverses its sign.

Thus,

The rule of reflection across the x-axis:

(x, y) → (x, -y)

so

A(-1, -8) → A'(-1, -(-8)) = A'(-1, 8)

B(-2, 2) → B'(-2, -2) = B'(-2, -2)

C(5, 2) → C'(5, -2) = C'(5, -2)

Then, translate the new triangle 5 units to the left

Rule of translating 5 units to the left

(x, y) → (x-5, y)

so

A'(-1, 8) → A''(-1-5, 8) = A''(-6, 8)

B'(-2, -2) → B''(-2-5, -2) = B''(-7, -2)

C'(5, -2) → C''(5-5, -2) = C''(0, -2)

Therefore, the coordinates of the vertices of the final image will be:

A''(-6, 8), B''(-7, -2), and C''(0, -2)

Hence, option (B) is true.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)