The graph for the system of inequalities without the shading of its solution set is shown on the coordinate grid. Choose the area that would be shaded to show the solution of this system.

9514 1404 393

  (C)  Area 3

Step-by-step explanation:

The first inequality has positive slope and a y-intercept of -5. The variable x has a positive coefficient so we can determine the shading from ...

  x ... > 5

That is, larger values of x are in the solution set. Shading is to the right of the line with positive slope, in areas 3 and 4.

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The second inequality has negative slope and a y-intercept of -3. Both x and y have positive coefficients, so the shading can be determined from either of ...

  ... 2y < -6 . . . . . . lower values of y are in the solution set

  x ... < -6 . . . . . . . lower values of x are in the solution set

These indicate the shading is below and to the left of the line with negative slope, in areas 2 and 3.

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The area that is in the solution set of both inequalities is Area 3.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]