Derivative of g(x) = 3x^2(x^2-(2/x)) I did derivative for each individual thing and got stuck at 6x(2x-2x^-2) so I am unsure what to do or what I did wrong​

When you are doing derivatives, you don't want to do it right away because there is still ( ) we need to remove that first get,

g(x)=3x^4-6x

Now we can do the derivatives!

g(x)=12*x^3 - 6

I hope this helps!

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

step-by-step explanation: