a $5 bill is exchanged for 72 coins having a total calue. of $5. Some of the coins are nickels and the rest are dimes. How many dimes are in the exchange?

Hi there!

Ok so we know that every nickel is €5 and every dime is €10...

Let think...

If it is 30 nickels it would be 150 cents and would also be 1.50$...

Now we know that there is 42 dimes left.. let see if it can be equaled.

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Adding both together would be 6.12 and it’s more than 5$ so this means that the nickels must be more.

Now let think again.. if it would be 44 nickels then the rest for 5.00 would be 2.20 and 72 subtract by 44 is 28. 28 multiply by 10 is perfectly 2.80.. now let check...

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Therefore, the total of dimes would be 28...

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )