What is the solution to the equation? 12 = |X| - 3 X= -36 or 36 X= -9 or 9 X = -4 or 4 X = -15 or 15​

x = -15 or 15

Step-by-step explanation:

We can simplify |x| - 3 = 15 to |x| = 15 because we can add 3 on both sides due to -3 being outside of the absolute value bars. Next, we can say that x is either 15 or -15 because of the absolute value (|15| is equal to 15 and |-15| is also equal to 15).

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a