A 22.4 kg object is accelerating at 1.40 m/s what net force is applied to the object

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

50- 250 is correct i did that one too

step-by-step explanation:

hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^