3x-5+6y-9+10x What are the variables?
How many terms?
What are the coefficients?
What are the constants?
What are the like terms?

ILL GIVE BRAINLIEST TO THE RIGHT ANSWER.

13x+6y-14

Step-by-step explanation:

3x-5+6y-9+10x

combine like terms,

3x+10x+6y-5-9

13x+6y-14

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°