ABCD is a rhombus. Given only the choices below, which properties would you use to prove AEB ≅ DEC by SAS? The diagonals are ⊥ to each other.

The diagonals bisect each other.

Opposite sides are | |.

All sides are congruent.

The diagonals bisect each other.

Step-by-step explanation:

Given

Rhombus ABCD

Required

Which property proves AEB ≅ DEC by SAS

From the question, we understand that the property is to be proved by SAS; SAS implies that Side-Angle-Side

We can assume that point E is where the diagonals meet.

So, we have:

Equal sides: AE = DE and BE = CD

Equal angle: <E = <E

The above implies that the diagonals bisect one another.

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step-by-step explanation:

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