Suppose that prices of recently sold homes in one neighborhood have a mean of $230,000 with a standard deviation of $6150. Using Chebyshev's Theorem, what is the minimum percentage of recently sold homes with prices between $217,700 and $242,300? Round your answer to one decimal place.

The percentage of recently sold homes with prices between $217,700 and $242,300

P( 2,17,700 ≤X≤2,42,300) = 95.44

Step-by-step explanation:

Step(i):-

Given that the mean the Population = 2,30,000

Given that the standard deviation of the Normal distribution = 6150

By using

 Let 'X₁' = 2,17,700

Let 'X₂' = 2,42,300

Step(ii):-

The probability that recently sold homes with prices between $217,700 and $242,300

P( 2,17,700 ≤X≤2,42,300) = P( -2≤Z≤2)

                                       = | A(2) + A(-2)|

                                       = |A(2) + A(2)|   (∵A(-z) =A(z)

                                      = 2× A(2)

                                     = 2×0.4772

                                    = 0.9544

Final -

The probability that recently sold homes with prices between $217,700 and $242,300

P( 2,17,700 ≤X≤2,42,300) = 0.9544

The percentage of recently sold homes with prices between $217,700 and $242,300

P( 2,17,700 ≤X≤2,42,300) = 95.44

step-by-step explanation:

i need to answer questions so i dont know but i think its the first one because it goes up but a consent rate

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

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