Bad gums may mean a bad heart. Researchers discovered that 80% of people who have su ered a heart attack had periodontal disease, an inammation of the gums. Only 30% of healthy people have this disease. Suppose that in a certain community heart attacks are quite rare, occurring with only 10% probability. If someone does not have periodontal disease, what is the probability that he or she will have a heart attack?

0.069 = 6.9% probability that he or she will have a heart attack

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not have periodontal disease

Event B: Has a heart attack.

Probability of not having a periodontal disease:

100 - 80 = 20% of 10%(had a heart attack).

30% of 100-10 = 90%(did not have a heart attack). So

Intersection of A and B:

Not having the disease, suffering a heart attack, so 20% of 10%.

What is the probability that he or she will have a heart attack?

0.069 = 6.9% probability that he or she will have a heart attack

where's the diagrams?

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints