Can someone pls help me
write 3lgx + 2-lgy as a single logarithm

log(x^3*y^(-2))

Step-by-step explanation:

two log rules you need to know for this question:

alogb = log(a^b)

logx + logy = logxy

you can start by getting rid of the term in front of the log, or a

also is it 2 minus or 2 times negative? im assuming it's 2 times negative because it is more likely

log (x^3) + log (y^-2) = log (x^3*y^-2)

john got lost so he didn't know what to do and it was crazy because he didn't except it

step-by-step explanation:

123123 step byt step