Two cars leave town at the same time and travel in opposite directions. Speed of car A is 12 km/h more than car B. They are 312km apart after 4 hours. Find the speed of each car.

Speed of car B is 33 km/h and speed of car A is

Step-by-step explanation:

Let speed of car B be km/h

Speed of car A is 12 km/h more than car B.

Therefore,

Speed of car A = km/h

Distance = Speed × Time

Distance travelled by car A in 4 hours = km = km

Distance travelled by car B in 4 hours = km

Also, cars A and B are 312km apart after 4 hours.

Speed of car B is 33 km/h and speed of car A is

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.