Perimeter/area (triangles)

12 ft²

50 ft²

Step-by-step explanation:

∆ABD = ∆CBD

Perimeter of ∆ABD = 12 ft²

Perimeter of triangle ∆CBD

If ∆ABD = ∆CBD

Then, Perimeter of ∆CBD = 12 ft²

∆ABC = ∆CDA

Area of ∆ABC = 25 ft²

Then the area of rectangle ABCD = Area of ∆ABC + Area of ∆CDA

= 25 ft² + 25 ft²

= 50 ft²

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.

can you put the picture up?

step-by-step explanation: