PLEASE HELP ASAP, GIVING BRAINLIEST TO CORRECT ANSWER The vertices of parallelogram ABCD are (2,4), B(0, 0), C(6,2), and D(8, 6). Find the coordinates of the intersection of the diagonals.

I believe it would be 4,3 not sure though

Step-by-step explanation:

The answer would be 4,3

Step-by-step explanation:

Graph the points on a graphing calculator, that should help when you need to find diagonals

answer: idk

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116