Help please :(

1

Step-by-step explanation:

The slope of a line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1x2−x1.

We have that x1=3, y1=2, x2=0, y2=−1.

Plug the given values into the formula for slope: m=(−1)−(2)(0)−(3)=−3−3=1.

Now, the y-intercept is b=y1−m⋅x1 (or b=y2−m⋅x2, the result is the same).

b=2−(1)⋅(3)=−1.

Finally, the equation of the line can be written in the form y=mx+b.

y=x−1.

The slope of the line is m=1.

The equation of the line in the slope-intercept form is y=x−1.

The equation of the line in the point-slope form is y−2=1(x−3).

The equation of the line in the point-slope form is y+1=1x.

The general equation of the line is x−y−1=0.

c > -10.55

step-by-step explanation: