A(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x- x-10 What is a+b?

a(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x^2-x-10

(x+1)(a(x-1)+b(x-2)+(x+1))=(x+1)(9x-10)

a(x-1)+b(x-2)+x+1=9x-10

Now this equation is much simpler!

(a+b)x-a-2b+x+1=9x-10

(a+b)x-a-2b=8x-11

(a+b-8)x-a-2b-11=0

a+b-8=(a+2b-11)/x

I can't solve it 3 variables and 1 equations means infinite answers so yea.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4