Please help me... Part A: Create at a system of liner equations with no solutions. In two or more complete sentences explain the specific characteristics that you have include in each equation to ensure that the system would not have a solution.
Part B: Using one of the equations that you created in part A create a system of liner equations that has one solution (x y)use substitution to solve the system.

answer: d. $20

step-by-step explanation:

just took the test

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

96 39 cause 135 -96=39 im smart (i used a calculater)