If a rectangle measures 21 centimeters by 28 centimeters what is the length in centimeters of the diagonal of the rectangle

35cm

Step-by-step explanation:

Given data

Length= 21cm

Width= 28cm

Diagonal= ???

Applying Pythagoras theorem

D^2= L^2+W^2

D^2= 21^2+28^2

D^2= 441+784

D^2= 1225

D= √1225

D= 35cm

Hence the diagonal is 35cm

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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