What is the student error in the multiplication below? Multiply the ones: 736 times 53 = 2198

Multiply the tens: 736 times 53 = 2,198. Above the 7 is 1 in 736, above the 3 in 736 is 3. 2,198 plus 36,800.

When multiplying the ones, the student did not carry over a ten to the next place in the first multiplication.
When multiplying the ones, the student should have found another product for 7 times 3.
When multiplying the tens, the student did not use the 0 place holder for the ones place.
When multiplying the tens, the student should have found another product for 6 times 5.

Step-by-step explanation:

1) When multiplying the ones, the student did not carry over a ten to the next place in the first multiplication.

2) When multiplying the ones, the student should have calculated 3 times 2 plus 5 as 11 and placed a 1 in the tens place.

3) When multiplying the tens, the student did not use the 0 place holder for the ones place.

4) When multiplying the tens, the student should have calculated 2 times 1 plus 9 as 11 and used a 1 should in the hundreds place.

The correct option is;

4) When multiplying the tens, the student did not use the 0 place holder for the ones place

Step-by-step explanation:

Here we have when doing long multiplication, the student correctly multiplies the ones as 2871, however, before commencing multiplication of the tens, a 0 should be placed in the ones place of the result as a place holder such that the outcome of the multiplication of the tens should be;

19140

Hence, the correct result should be 2871 + 19140 = 22011

The correct option is therefore, that "When multiplying the tens, the student did not use the 0 place holder for the ones place."

answer: was that a question or answer?

step-by-step explanation:

i think it is c, not positive though

step-by-step explanation: