3. 8.6.2.8
Triangle ABC has
vertices A (0, -4), B (5,
-4) and C (5,8). What
Is the length, in units,
of AC.

9514 1404 393

  13 units

Step-by-step explanation:

The distance formula is useful for this.

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((5 -0)² +(8 -(-4))²) = √(25 +144) = √169

  d = 13

The length of AC is 13 units.

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0