Solve this system of equations.

3x+4y=4
-x-3y=7

x = 8, y = -5

Step-by-step explanation:

Multiplying the 2nd equation by 3, we get -3x-9y = 21. Then eliminating with the first equation we get -5y = 25. y = -5. Substituting this into the original equation, we get x = 8.

x=8  y=-5

Step-by-step explanation:

3x+4y=4                   3x+4y=4

3(-x-3y=7)=              -3x-9y=21

-3x-9y=21                      -5y=25

                                       y=-5

3x+4(-5)=4

3x-20=4

3x=24

x=8

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.

my dear correct answer is option number 3