UNSOLVEABLE . I will Mark Brainliest Given square ABCD. Two isosceles triangles ABP and BCQ are constructed with bases AB and BC . Each of these triangles has vertex angle of 80°. Point P lies in the interior of the square, while point Q lies outside of the square. Find the angle measure between PQ and BC

please get this correct no one else has been able to solve

I'm Not Sure

Step-by-step explanation:

Transcript. Ex7.2, 5 ABC and DBC are two isosceles triangles on the same base BC (see the given figure). Show that ∠ABD = ∠ACD. Given: ΔABC is isosceles So, AB = AC ΔDBC is isosceles So, DB = DC To prove: ∠ ABD

Step-by-step explanation:

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

more detail

step-by-step explanation: