subject
Mathematics, 19.02.2021 02:10 YaGirlNeedaLearn

An employment recruitment firm is interested in knowing what percentage of workers is routinely late for work. An employee of the firm surveys a random sample of 65 people who have hired the firm that week to help them find employment. She asks them whether they were late for work more than 2 times a month, on average, in their last position. Of the 65 people, 17 respond that they were late for work more than 2 times a month, on average, in their last position. The employee constructs a 95% confidence interval for the proportion of workers who were late for work more than 2 times a month, on average, in their last position and obtains the interval (0.160, 0.385). Which of the following is the best example of a source of error that may cause the interval not to contain the true proportion of workers who were late more than 2 times a month, on average, in their last position? The sample only is representative of the people who hired the firm that week, and other workers may be different with respect to how often they are late for work.
Some workers may have lied and said “no” because they feared that they would not be hired again, causing the true proportion to be higher than any of the values in the interval.
Some workers may have lied and said “yes” because they wanted the employment firm to think they were regularly late to work, causing the true proportion to be lower than any of the values in the interval.
Some workers may have said “no” because they do not know whether they were late more than 2 times a month, on average, causing the true proportion to be higher than any of the values in the interval.
Some workers may have incorrectly thought they had been late more than 2 times a month, on average, when they actually had not, so they would answer “yes,” causing the true proportion to be lower than any of the values in the interval.

ansver
Answers: 1

Another question on Mathematics

question
Mathematics, 21.06.2019 20:00
The weight v of an object on venus varies directly with its weight e on earth. a person weighing 120 lb on earth would weigh 106 lb on venus. how much would a person weighing 150 lb on earth weigh on venus?
Answers: 2
question
Mathematics, 21.06.2019 21:00
When solving this problem: 3025/5.5 = a/90.75 you get 49912.5 which would be the length of one of the sides of a square when the area is only 90.75 inches. is that answer correct, why, and how is it possible?
Answers: 1
question
Mathematics, 22.06.2019 07:30
Answer asap will give bob solved the inequality problem below incorrectly. explain his error and redo the problem showing the correct answer. −2x + 5 < 17 −2x + 5-5 < 17-5 -2x/-2 < 12/-2 x < -6
Answers: 1
question
Mathematics, 22.06.2019 09:00
The identity function i behaves just like the number 1. that is (f o i)=f and (i o g)= g it is also true that for a function k, (k o k^-1)=i use this information and algebra to solve h= (f o g) for f any insight would be !
Answers: 1
You know the right answer?
An employment recruitment firm is interested in knowing what percentage of workers is routinely late...
Questions
question
Social Studies, 22.07.2019 07:30
Questions on the website: 13722367