Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 6.0 parts/million (ppm). A researcher believes that the current ozone level is not at a normal level. The mean of 13 samples is 5.6 ppm with a variance of 0.49. Assume the population is normally distributed. A level of significance of 0.1 will be used. Find the value of the test statistic. Round your answer to three decimal places.

Test statistic | t| = |-2.0607| = 2.0607

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 6.0 parts / million

The mean of sample x⁻ = 5.6ppm

The variance of the sample = 0.49

The standard deviation of the sample (s) = √0.49 = 0.7

Step(ii):-

Test statistic

            t = -2.0607

Final -

Test statistic | t| = |-2.0607| = 2.0607

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!