A weight of 6 lb stretches a spring a distance of 12 in. Find the constant k for the spring.

6 Ib

Step-by-step explanation: 12-6=6

Let F = the force (6 lbs) and x be the distance that the spring is stretched (12 inches).

F = kx

6 lb = k*(12 in.)

6/12 = k = 0.5 lb/in.

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

step-by-step explanation:

f