A jar contains 6 yellow and 8 blue gumballs. Two gumballs will be drawn at random without being replaced. If the first gumball drawn is blue, what is the probability that the second gumball will also be blue?

I believe the answer would be 8/13 or 61.5%.

Step-by-step explanation:

Hope this helps :))

good for u

step-by-step explanation:

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )