Which could not be a set of intervals for a frequency table or a histogram? A.0–4, 5–9, 10–14, 15–19, 20–24
B.1–5, 6–10, 11–15, 16–20, 21–25
C.1–10, 11–20, 21–30, 31–40, 41–50
D.0–5, 5–9, 10–15, 15–20, 20–25

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people