The half-life of hellium-5 is 7.6x10^-22 seconds, and the half-life of hellium-9 is 7x10^-21 seconds. Approximately how many times greater is the half-life of hellium-9 than that of helium-5?

9.2 times greater

Step-by-step explanation:

Given that :

Half life :

Helium - 9 = 7x10^-21 seconds

Helium - 5 = 7.6x10^-22 seconds

To obtain the number of tunes helium - 9 half life is greater than helium - 5 ; we divide the half life of helium-9 by the half life of helium 5

7x10^-21 seconds / 7.6x10^-22 seconds

0.9210526 x 10^(-21 - (-22))

0.9210526 * 10^1

= 0.9210526 * 10

= 9.2105

About 9.2 times greater

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

answer: it's d

step-by-step explanation: