Activity 3. Convert the following to the indicated measurement:
1. 86 km
dam
9. 6, 600 min
hr
10. 415° F
2. 2 mi
in
3. 20 in
cm
11. 130 °C
-
F
4. 25.1 gal
الي
12. 2.3 gallon
qt
5. 45 acre
km
13. 632 ft
cord
6. 67.33 at
gal
14. 5.1 lb
grains
7. 90.67 km
ha
15. 1,800 oz
- kg
8. 6 days​

Activity 3.

Convert the following to the indicated measurement:

1. 86 km = 8600 dam

9. 6, 600 min = 110 htlrs

10. 415° F = 212.778° c

2. 2 mi = 126720 in

3. 20 in = 50.8 cm

11. 130 °C = 266° F

4. 25.1 gal = 100.4 qt

12. 2.3 gallon = 9.2 qt

5. 45 acre = 0.174 square km

13. 632 ft = 4.937 cords

6. 67.33 qt = 16.832 gallons

14. 5.1 lb = 35700 grains

7. 90.67 km = 9067 hectares

15. 1,800 oz = 51.029 kilograms

8. 6 days = 144 hours = 8640 minutes

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80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752