Identify the values of a, b, and c that could be used with the quadratic formula to solve the equation. Enter a as a positive integer value. x^(2)=6(x-8)

A=
B=
C=

THANK YOU SO MUCH

a=1

b= -6

c=48

Step-by-step explanation:

x^2=6(x-8)

x^2=6x-48

x^2-6x+48

a,b are the coefficients of x^2 and x

c is the constant value present

Therefore it is basically written as ax^2+bx+c

and comparing with the answer x^2-6x+48,

a=1, b= -6, c=48

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

it has the same slope and a different y-intercept

hope this : )