The perimeter of a rectangle is 35cm. The length is 5cm. Write and solve an equation to find the width of the rectangle.

P = 2L + 2W

35 cm = 2(5 cm) + 2(W cm)

W = 12.5 cm

Step-by-step explanation:

P = 2L + 2W

35 cm = 2(5 cm) + 2(W cm)

35 cm - 10 cm = 2W cm

2W cm = 25 cm

w cm = 12.5 cm

Step-by-step explanation:

step 1. a rectangle has 2 sets of congruent sides; we will call them l and w.

step 2. P (perimeter) = l + l + w + w = 35

step 3. 35 = 5 + 5 + 2w

step 4. 25 = 2w

step 5. w(width) = 12.5 cm.

c is the final : )

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: