![\sqrt[3]{x} = \sqrt[3]{t^3}](/tpl/images/1133/5853/ab17b.png)
![\sqrt[3]{x}=t](/tpl/images/1133/5853/1b92c.png)
Now square both sides![(\sqrt[3]{x})^2 = t^2](/tpl/images/1133/5853/e29a2.png)
- 2If x = t^3 and y = t^2 - 2 , what is y in terms of x?
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