Find the equation of a line perpendicular to 3x−4y=6 that contains the point (2,−4).

y= -4x/3 - 4/3

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=3x4−32.

The slope of the perpendicular line is negative inverse: m=−43.

So, the equation of the perpendicular line is y=−4x3+a.

To find a, we use the fact that the line should pass through the given point: −4=(−43)⋅(2)+a.

Thus, a=−43.

Therefore, the equation of the line is y=−4x3−43.

Step-by-step explanation:

y=mx+b

3x-4y=6

4y=3x-6

y=(3x-6)/4

So the slope, m, is 3/4

For lines to be perpendicular m1(m2)=-1, in this case

3m/4=-1

m=-4/3 so our line so far is

y=-4x/3+b, using point (2,-4) we can solve for the y intercept or b

-4=-4(2)/3+b

b=-4/3 so

y=(-4x-4)/3

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).