each of equal sides of an isosceles triangle is 4cm greater than its height .If the base of triangle is 24 cm ,calculate the perimeter and the area of the triangle​

192 cm²

Let us take the height be x , then its side = x + 4. Now half of base will be 12 cm .

According to Pythagoras Theorem :-

=> base² + perpendicular ² = hypontenuse ²

=> 12² + x² = (x+4)²

=> 144 + x² = x² + 16 + 8x

=> 8x = 144-16

=> 8x = 128

=> x = 128/8

=> x = 16 cm .

Hence the height of ∆ is 16 cm .So the area will be half the product of base and altitude.

= 1/2 * 16 cm * 24cm .

= 192 cm²